Using euclids division algorithm find the HCF of 240 and 228
Answers
Answered by
2
hey dude as you know that the prime factorization of
240=2*2*2*2*3*5
228=2*2*3*19
now HCF=2*2*3=12
hope it helps u
240=2*2*2*2*3*5
228=2*2*3*19
now HCF=2*2*3=12
hope it helps u
gurgjkusfoodti:
it is not ecludes division lema
Answered by
3
Hello friend
Your answer is given below
______________________________
We know that
Euclid's division lemma
=> a = bq + r ( 0<r < b )
=> So , 240 > 228
Therefore
=> 240 = 228 × 1 + 12
=> 228 = 12 × 19 + 0
=> So here remainder is 0
=> So the answer is 12.
=> The HCF ( 240,228) = 12
_______________________________
I hope it will help you
Thanks
Have a great day
Your answer is given below
______________________________
We know that
Euclid's division lemma
=> a = bq + r ( 0<r < b )
=> So , 240 > 228
Therefore
=> 240 = 228 × 1 + 12
=> 228 = 12 × 19 + 0
=> So here remainder is 0
=> So the answer is 12.
=> The HCF ( 240,228) = 12
_______________________________
I hope it will help you
Thanks
Have a great day
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