Using euclids division lemma find the hcf of 867 and 255
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Answered by
9
Euclid's Division Lemma =
a = bq + r
Given Numbers = 867,225
Finding HCF (Highest Common Factor) :
867 = 225×3+192
225 = 192×1+33
192=33×5+27
33=27×1+6
27=6×4+3
6=3×2+0
The required HCF is = 3
a = bq + r
Given Numbers = 867,225
Finding HCF (Highest Common Factor) :
867 = 225×3+192
225 = 192×1+33
192=33×5+27
33=27×1+6
27=6×4+3
6=3×2+0
The required HCF is = 3
Answered by
4
since 867 > 255,we apply the division lemma to 867 and 255 to obtain
867=255×3+102
since remainder 102≠0,we apply he division lemma to 255 and 102 to obtain
255=102×2+51
we consider, the new divisor 102 and new remainder 51, and the division lemma to obtain
102=51×2+0
since the remainder is 0,the process stops
since the divisor at this stage is 51
Therefore the HCF of 867 and 255 is 51
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