using eulid's division algorithm, find the hcf of the following. (i) 26and 91 ,(ii) 504and 908.,(iii) 135 and 714.,(iv) 2815 and 70625.please friends all question solve please.
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91=26×3+13
26=13×2+0
hence ,h.c.f (26,91)=13
26=13×2+0
hence ,h.c.f (26,91)=13
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