Question

using
evalid's division algorithm. fund
the
HCF
of 448 and 304
Sol​

Answer 1

Answer:

• The divisor at this stage, ie, 16 is the HCF of 4052 and 304.

Given :

• 448 and 304.

To find :

• H. C. F of 448 and 304.

Step-by-step explanation:

Clearly, 448 > 304

Applying the Euclid's division lemma to 448 and 304, we get

448 = 304 × 1 + 144

Since the remainder 144 ≠ 0, we apply the Euclid's division lemma to divisor 448 and remainder 144 to get

304 = 144 × 3 + 16

We consider the new divisor 144 and remainder 16 and apply the division lemma to get

144 = 16 × 9 + 0

Now, the remainder at this stage is 0.

So, the divisor at this stage, ie, 16 is the HCF of 4052 and 304.

Answer 2

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