Question

Using F.O.I.L Method, solve the following word problem: What is the area of a pool whose width is x+2 meters and whose length is four meters more than its width​

Answer 1

Step-by-step explanation:

LET THE WIDTH BE = x + 2

LET THE LENGTH BE = 4 ( x + 2 )

AREA OF POOL ( RECTANGLE ) = Length × Breadth

THEN,

• x + 2 × 4 ( x + 2 )
• x + 2 × 4x + 8
• 5x = 10
• x = 10/5
• x = 2

WIDTH = ( X + 2 ) = 2 + 2 = 4 m

LENGTH = { 4 ( x + 2 )} = { 4 × 4 } = 16 m

hence width is 4 m

and length is 16 m

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