Using factor method divide 1-x^6 by 1-x^2
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Answer:
(1-x^6)÷(1-x^2)
={(1)^3-(x^2)^3}÷(1-x^2)
=(1-x^2){1^2+1×x^2+(x^2)^2}÷(1-x^2)
=1+x^2+x^4Ans
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