Question

using factor method divide polynomial (y^2-y-42) by (y-7)​

Answer 1

Answer:

y−7

y

2

−y−42

= y + 6

Step-by-step explanation:

We have,

Divide the polynomial (y^2y

2

- y - 42) by (y - 7)

To find, the divide the polynomial (y^2y

2

- y - 42) by (y - 7) = ?

By factors method,

∴ \dfrac{y^{2}-y-42}{y-7}

y−7

y

2

−y−42

= \dfrac{y^{2}-7y+6y-42}{y-7}

y−7

y

2

−7y+6y−42

= \dfrac{y(y-7)+6(y-7)}{(y-7)}

(y−7)

y(y−7)+6(y−7)

= \dfrac{(y-7)(y+6)}{(y-7)}

(y−7)

(y−7)(y+6)

The numerator and denominator having (y - 7) is cancel.

= y + 6

The divide the polynomial (y^2y

2

- y - 42) by (y - 7) = y + 6

Thus, \dfrac{y^{2}-y-42}{y-7}

y−7

y

2

−y−42

= y + 6