Question

Using factor method divide the polynomia (y2-y-42)by (y-7)

Answer 1

Answer:

you have to just divide the polynomial by first factor by long division method and then the question will be your second factor

Answer 2

$\dfrac{y^{2}-y-42}{y-7}$= y + 6

Step-by-step explanation:

We have,

Divide the polynomial ($y^2$ - y - 42) by (y - 7)

To find,  the divide the polynomial ($y^2$ - y - 42) by (y - 7) = ?

By factors method,

∴ $\dfrac{y^{2}-y-42}{y-7}$

= $\dfrac{y^{2}-7y+6y-42}{y-7}$

= $\dfrac{y(y-7)+6(y-7)}{(y-7)}$

= $\dfrac{(y-7)(y+6)}{(y-7)}$

The numerator and denominator having (y - 7) is cancel.

= y + 6

The divide the polynomial ($y^2$ - y - 42) by (y - 7) = y + 6

Thus, $\dfrac{y^{2}-y-42}{y-7}$= y + 6