Question

using factor method divide y²+3y-10 by (x-2)​

Answer 1

Answer:

${y}^{2} + 3y - 10 = {y}^{2} + 5y - 2y - 10 \\ \\ = y(y + 5) - 2(y + 5) \\ \\ = (y - 2)(y + 5). \\ \\ therefore \: \: \: \: ({y}^{2} + 3y - 10) \: when \: divided \: by \: (y - 2) \: \: \: \: we \: get \: \: \: (y + 5).$