Question

using factor theoram​

Answer 1

If (x-2) is a factor of the polynmial f(x) = (x^3-8), then by factor theorem, f(2) should be equal to zero;

$or \: \:f(2) = {2}^{3} - 8 \\ = 8 - 8 \\ = 0$

Hence, it is proved that (x-2) is a factor of f(x).

HOPE THIS COULD HELP!!!