using factor theorem factorise 2a4+a3-14a2-19a-6
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We have been given the following expression:
2a^4+a³-14a²-19a-6
Taking the first two terms 2a^4 + a³,
we take a³ common to get a³(2a + 1) ---------------- (i)
Taking the last three terms together we have 14a² + 19a + 6
Factorizing we get (7a+6)((2a+1) ------------------ (ii)
Putting (i) and (ii) together we get
a³(2a + 1) - (7a + 6)(2a + 1)
Taking (2a + 1) common, we get
(2a + 1)(a³ - 7a - 6) - our answer
2a^4+a³-14a²-19a-6
Taking the first two terms 2a^4 + a³,
we take a³ common to get a³(2a + 1) ---------------- (i)
Taking the last three terms together we have 14a² + 19a + 6
Factorizing we get (7a+6)((2a+1) ------------------ (ii)
Putting (i) and (ii) together we get
a³(2a + 1) - (7a + 6)(2a + 1)
Taking (2a + 1) common, we get
(2a + 1)(a³ - 7a - 6) - our answer
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