Math, asked by sangampandey43, 1 year ago

Using factor theorem factorise 2y^3+y^2-2y-1

plzz give its answer.............


michealjackson143: 1, -1, -1/2
michealjackson143: are the factors

Answers

Answered by Thatsomeone
7

\huge {\textbf {\underline  {\underline  {ANSWER}}}}

2y^3 + y^2 - 2y - 1

= y^2( 2y + 1 ) - 1 ( 2y + 1 )

= ( 2y + 1 )( y^2 - 1 )

= ( 2y + 1 )( y + 1 )( y - 1 )


michealjackson143: someone already posted it
Anonymous: Kk.
sangampandey43: is it incorrect???
MADBRO: no
michealjackson143: what..?
MADBRO: it's right
michealjackson143: its correct..
MADBRO: yep
Thatsomeone: thanks for brainliest
sangampandey43: my pleasure....
Answered by MADBRO
4
Hi..

answer in attachment :)

#tq
Attachments:

Anonymous: Check it out!
Anonymous: It should be y-1
Anonymous: Last 3 steps r wrong...
MADBRO: woh
MADBRO: aur kya
sangampandey43: i haved checked
MADBRO: + - hi hain
sangampandey43: there was a little bit of mistake
MADBRO: now I have done it
Anonymous: Kk..
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