using factor theorem factorise each of the following polynomials x cube minus 6 X square + 3 X + 10
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Answer:
(x+1)(x−2)(x−5) .
Step-by-step explanation:
- Apply trial and error to the equation by substituting x as any random integer to the equation x3−6x2+3x+10=0. If the equation gives a result of 0, then (x - root) will be one factor of the equation.
- In thaT case, consider x = 2, so 23−6(2)2+3(2)+10=0
8−24+6+10=0
- Hence, (x - 2) is one of the roots of the equation.
- Now, apply long division, and accordingly we will obtain another factor as x2−4x−5=(x−5)(x+1).
- Hence, x3−6x2+3x+10=(x+1)(x−2)(x−5) .
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