Using factor theorem factorise (i) x3 +6x2 +12x+8 (ii) 6x3 +53x2 -21x-108 (iii) t3 -7t+6
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Answer:
Explanation:
The Expression
=
x
3
+
6
x
2
+
12
x
+
8
=
(
x
3
+
8
)
+
6
x
(
x
+
2
)
=
(
x
+
2
)
−−−−−−−
(
x
2
−
2
x
+
4
)
+
6
x
(
x
+
2
)
−−−−−−−
=
(
x
+
2
)
{
x
2
−
2
x
+
4
+
6
x
}
=
(
x
+
2
)
(
x
2
+
4
x
+
4
)
=
(
x
+
2
)
{
x
2
+
2
(
2
)
(
x
)
+
2
2
}
=
(
x
+
2
)
(
x
+
2
)
2
=
(
x
+
2
)
3
.
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Answered by
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(I) 3x + 6×2 + 12x+8
= 15x + 12 + 8
= 15x + 20
= 5(3x+4)
= (5+0)(3x+4)
Either ,
5+0 = 0. or. 3x+4 = 0
5=0. or. 3x = -4
not possible. or x = -4/3
Therefore, x = -4/3
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