using factor theorem factorise the polynomial x3+x2-4x-4
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Step-by-step explanation:
By Factorising we get
x^3 + x^2 - 4x - 4 = (x+1) (x+2) (x-2)
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★ p(x) =x^3 + x^2 - 4x - 4
now, put the value of x= -1
p( -1) = (-1)^3 + (-1)^2 -4(-1) -4
= -1 +1 +4 - 4
= 5-5
=0
so, (x + 1) is a factor of p(x).
______________
x+1 ) x^3 + x^2 -4x -4 ( x^2 - 4
x^3 + x^2
- -
0 -4x -4
-4x -4
+ +
×
:- ( x+1) [ x^2 - 4]
:- ( x+1 ) [ x^2 -2x +2x -4]
:- ( x+1 ) [ x(x-2) +2(x-2) ]
:- (x+1) (x+2) (x-2) } -: answer
so, (x+1) (x+2) (x-2) are the factors of p(x).
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