Question

Using factor theorem factorize 2y3-5y2-19y+42

Answer 1

Answer:

(y-2)(2y-7)(y+3)

Step-by-step explanation:

2y3-5y2-19y+42

factors of 42= +/- 1,+/-2, +/-3,+/-6,+/-7,+/-14,+/-21,+/-42

p(y)=1

2(1)3-5(1)2-19(1)+42=2-5-19+42 = -14+44(not equal to 0)

p(y)=-1

2(-1)3-5(-1)2-19(-1)+42= -2-5+19+42

= -7+61( not equal to 0)

(balance on photo)