Using factor theorem, factorize each of the following polynomials: (i) x 3– 6x 2 + 3x + 10 (ii) 2y 3– 5y 2 – 19y + 42
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Step-by-step explanation:
let F(y)=2y³-5y²-19y+42
Constand term=42
Factors of 42=+1,+2,+3,+6,+7,+14,+21,+42.
Now,
divide F(y) by (y-2) we get,
y-2÷2y³-5y²-19y+42
2y³-4y²
-y²-19y
-y²+2y
-21y+42
-21y+42
0
F(y)=(y-2)(2y²-y-21)
=(y-2)(2y²-7y+6y-21)
=(y-2)y(2y-7)+3(2g-7)
therefore, F(y)=(y-2)(2y-7)(y+3)
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