using factor theorem find the value of 'a' for which the polynomial (x^4 - x^3 - 11x^2 - x + a) is divisble by (x+3)
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By factor Theorem
x + 3 = 0
x = -3
________________
p(x) = x⁴-x³-11x²-x+a = 0
p(-3) = (-3)⁴ - (-3)³ -(-3) + a = 0
81 + 27 +3 + a = 0
111 + a = 0
a = -111
_________________
Hence, value of a will be -111 for which p(x) will be divisible by (x+3)
Answered by
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Answer:
By factor Theorem
x + 3 = 0
x = -3
________________
p(x) = x⁴-x³-11x²-x+a = 0
p(-3) = (-3)⁴ - (-3)³ -(-3) + a = 0
81 + 27 +3 + a = 0
111 + a = 0
a = -111
_________________
Hence, value of a will be -111 for which p(x) will be divisible by (x+3)
Step-by-step explanation:
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