using factor theorem find x minus 2 is a factor of x cube minus 8
Answers
Answered by
24
g(x)=x-2=0,x=2,p(x)=x^3-8
put x in p(x).
2^3-8
8-8
0
so,x^3 is a factor of x-2.
put x in p(x).
2^3-8
8-8
0
so,x^3 is a factor of x-2.
Answered by
28
Answer:
x-2 is a factor of x ³-8
Step-by-step explanation:
x-2
x-2=0
x=2
p(x)=(x³-8)
p(2)=(2)³-8
=8-8
=0
hope this helped you.
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happy to help you.
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