Question

Using factor theorem p(x) = x3 – 4x2 + x + 6 , g(x) = x- 3

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

let x-3=0

let x-3=0 x=3

let x-3=0 x=3 p(3) = (3)^3 -4×3^2 + 3 +6

let x-3=0 x=3 p(3) = (3)^3 -4×3^2 + 3 +6 = 27-36+9

let x-3=0 x=3 p(3) = (3)^3 -4×3^2 + 3 +6 = 27-36+9 =-8+9

let x-3=0 x=3 p(3) = (3)^3 -4×3^2 + 3 +6 = 27-36+9 =-8+9 =17

let x-3=0 x=3 p(3) = (3)^3 -4×3^2 + 3 +6 = 27-36+9 =-8+9 =17 Plz mark me brainliest!!!!!!!!!