Question

using factor theorem show that [2x-3] is a factor of [2x4 +x3-8x2-x+6]

Answer 1

Step-by-step explanation:

let P(x)=2x^4+x^3-8x^2-x+6

put 2x-3=0

x=3/2

P(3/2)=2(3/2)^4+(3/2)^3-8(3/2)^2-3/2+6

=2×81/16+27/8-8×9/4-3/2+6

=81/8+27/8-18-3/2+6

=108/8-12-3/2

=108-96-12/8

=0/8

=0

so by factor theorm

2x-3 is factor of p(x)

Answer 2

Answer:

Step-by-step explanation

Put 2x3=0

x(3/2)=2(3/2)²