Question

using factor theorem show that g(x) is a factor if p(x) when - p(x) = 2√2x² + 5x + √2 , g(x) = x+√2


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Answer 1

p(x)= 2√2x²+5x+√2, g(x)= x+√2

g(x)= 0

x+√2= 0

x= -√2

Substituting values-

p(-√2)= 2√2(-√2)²+ 5(-√2)+ √2

         = 2√2×2+ (-5√2) +√2

         = 4√2 -5√2 +√2

         = 5√2 -5√2

         = 0

Therefore, g(x) is a factor of p(x).

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