Question

using Factor theorem, show that g(x) is a factor of P(x) when

P(X) - x^3-8 g(x)= x-2​

Answer 1

Step-by-step explanation:

use factor Theorem

g(x)=x-2=0

=x=0+2=2

=x^3-8

(2)^3-8

=8-8=0

g(x) is a factor of p(x).