Math, asked by rishav61, 1 year ago

using factor theorem, show that g(x) is the factor of p(x) when, p(x)=x³-8,g(x)=x-2.

Answers

Answered by skh2

Hello,

Please refer the above photograph for the used process

Hope this will be helping you ✌️

Attachments:

rishav61: Can i solve this sum as a remainder theorem?

skh2: yes,

rishav61: then what is the difference between factor theorem and remainder theorem?

skh2: see, when a polynomial is there p(x) and another polynomial g(x)

skh2: so, p(x) ÷g(x)

skh2: so, the remainder is r(x)

skh2: now, if g(x) is x-a

rishav61: i know the answer but only for knowing the process and the difference between remainder theorem and factor theorem i have asked this sum.

skh2: then by remainder theorem we can say that if p(x) is divided by g(x) then the remainder will be p(a)

skh2: now, if p(x) is divided by g(x) then if p(a) =0, then g(x) is a factor of p(x)

Answered by Shivanshi98

use factor theorem

g(x)=x-2=0

=x=0+2=2

=x^3-8

(2)^3-8

=8-8=0

g(x) is a factor of p(x)

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