using factor theorem, show that g(x) is the factor of p(x) when, p(x)=x³-8,g(x)=x-2.
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Answered by
34
Hello,
Please refer the above photograph for the used process
Hope this will be helping you ✌️
Please refer the above photograph for the used process
Hope this will be helping you ✌️
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rishav61:
Can i solve this sum as a remainder theorem?
yes,
then what is the difference between factor theorem and remainder theorem?
see, when a polynomial is there p(x) and another polynomial g(x)
so, p(x) ÷g(x)
so, the remainder is r(x)
now, if g(x) is x-a
i know the answer but only for knowing the process and the difference between remainder theorem and factor theorem i have asked this sum.
then by remainder theorem we can say that if p(x) is divided by g(x) then the remainder will be p(a)
now, if p(x) is divided by g(x) then if p(a) =0, then g(x) is a factor of p(x)
Answered by
20
use factor theorem
g(x)=x-2=0
=x=0+2=2
=x^3-8
(2)^3-8
=8-8=0
g(x) is a factor of p(x)
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