using factor theorem show that the polynomial x^3-2x^2+3x-18 is a multiple of x-3
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Answer:
x-3=0
'x=3
putx=3
3×3×3-2×3×3+3×3-18
27-18+9-1
36-36=0
hence it prove that x - 3 is a factor of the given polynomials because when we put x = 3 the polynomial cames zero
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