Question

Using factor theorem show that (x+1) is a factor of x^19+1

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Answer 1

Step-by-step explanation:

p(x) = x^19 +1

p(-1) = (-1)^19 + 1 = -1 +1 = 0

p(-1) = 0. This means on putting -1 in p(x) , we get 0.

Hence , by factor theorem we can conclude that (x+1) is a factor of x^19 +1