Question

using factor theorem, show that (x-2) is a factor of f(x) = x^3-5x^2+2x+8​

Answer 1

Answer:

OMG i dont know

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Answer 2

Answer:

yes

Step-by-step explanation:

x-2

so x=2

now put the value x=2in f(x) by using factor theorem

f(x)=2^3-5x2^2+2x2+8

=8-5x4+4+8

=8-20+4+8

=20-20

=0

hence answer is 0,so x-2 is a factor of f(x)