Question

using factor theorem show that (x-2) is a factor of x^3+x^2-4x-4. Factorise completely.​

Answer 1

Answer:

(x) = 0

Step-by-step explanation:

x = 2 [ x - 2 = 0 ]

Putting the value of x in equation,

$= {2}^{3} + {2}^{2} - {4}(2) - 4$

= 8 + 4 - 8 - 4

= 0

Answer 2

Step-by-step explanation:

x=2 [x-2=0]

Put the value of x on equation

=2+2-4(2)-4

=8+4-8-4

=0