Question

using factor theorem show that (x-2) is a factor of x³-2³​

Answer 1

Let p(x)=x³-2³

Divisor=x-2

x-2=0

x=2

By remainder theorem,

Remainder=p(2)

=2³-2³

=8-8

Remainder=0

therefore, By factor theorem,

x-2 is a factor of x³-2³