using factor theorem show that x² + 5x +6 is a factor of x⁴+5x³+9x²+15x+18
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33
By using factor theorem,
x² + 5x + 6
Factorising
x² + 2x + 3x + 6
x(x + 2) + 3(x + 2)
(x + 3)(x + 2)
Zeroes -
x = -3, -2
substituting -
x⁴ + 5x³ + 9x² + 15x + 18
= (-2)⁴ + 5(-2)³ + 9(-2)² + 15(-2) + 18
= 16 - 40 + 36 - 30 + 18
= 0
So, x² + 5x + 6 is a factor of x⁴ + 5x³ + 9x² + 15x + 18.
x² + 5x + 6
Factorising
x² + 2x + 3x + 6
x(x + 2) + 3(x + 2)
(x + 3)(x + 2)
Zeroes -
x = -3, -2
substituting -
x⁴ + 5x³ + 9x² + 15x + 18
= (-2)⁴ + 5(-2)³ + 9(-2)² + 15(-2) + 18
= 16 - 40 + 36 - 30 + 18
= 0
So, x² + 5x + 6 is a factor of x⁴ + 5x³ + 9x² + 15x + 18.
Answered by
2
Answer:
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Step-by-step explanation:
16 16 - 40 + 36 - 30 + 18 is equals to 0
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