Using factor theorum,
Show that (a-b) is a factor of a (b²-c²)+b (c²-a²) + c (a²-b²)
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Answer:
a-b= 0
a = b
by putting the value in equation.
b(b^2-c^2)+b(c^2-b^2)+c(b^2-b^2)
b^3-bc^2+bc^2 -b^3 +c(0)
terms will get cancelled.
c(0)= 0.
answer is 0 , therefore (a-b) is a factor of the above equation.
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