Using factor therom
therom show that (x+4) is
factor
of x² + 10x + 24
Answers
Answered by
0
Answer:
Given polynomial,
p(x) = x³ - 3x² - 10x + 24
To show: ( x - 2 ) , ( x + 3 ) and ( x - 4 ) are factors of p(x)
We use Factor Theorem which states that if x - a is factor of p(x) then p(a) = 0.
we check for ( x - 2 )
p(2) = (2)³ - 3(2)² - 10(2) + 24 = 8 - 12 - 20 + 24 = 32 - 32 = 0
So, ( x - 2 ) is factor of p(x).
we check for ( x - 4 )
p(4) = (4)³ - 3(4)² - 10(4) + 24 = 64 - 48 - 40 + 24 = 88 - 88 = 0
So, ( x - 4 ) is factor of p(x).
we check for ( x + 3 )
p(-3) = (-3)³ - 3(-3)² - 10(-3) + 24 = -27 - 27 + 30 + 24 = 54 - 54 = 0
So, ( x + 3 ) is factor of p(x).
Hence, Proved.
Similar questions