Question

Using factorisation find the roots of the quadratic equation y^2+2√3y+3=0​

Answer 1

y² + 2√3y + 3 = 0

=> Sum of roots = - 2√3 and

product of roots = + 3

=> y² + √3y + √3y + 3 = 0

=> y ( y + √3 ) + √3 ( y + √3 ) = 0

=> ( y + √3 ) ( y + √3 ) = 0

=> ( y + √3 )² = 0

=> y = -√3 and -√3

so, these numbers satisfy the above conditions too .

Answer 2

Step-by-step explanation:

I think you should understand this answer