Question

using factorisation find the roots of the quadratic equation 3√2x^2-5x-√2=0

Answer 1

According to given sum,

$3 \sqrt{2} {x}^{2} - 5x - \sqrt{2} = 0$
i)
$3 \sqrt{2} \times ( - \sqrt{2} ) = - 6$

product of two numbers is -6 & sum of numbers should be -5 . so Those numbers are
-6 & 1 .

$3 \sqrt{2} {x}^{2} - 6x + x - \sqrt{2} = 0$

$\frac{6}{ \sqrt{2} } {x}^{2} - 6x + x - \sqrt{2} = 0$

$\frac{6}{ \sqrt{2} } x(x - \sqrt{2}) + 1(x - \sqrt{2} ) = 0$

$(x - \sqrt{2} )( \frac{6}{ \sqrt{2} }x + 1) = 0$

$x = \sqrt{2} \: or - \frac{ \sqrt{2} }{6}$

:-)Hope it helps u.

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