Question

Using factorisation method find the root of equations
1) y^2 + 2root3y + 3 = 0
2)x^2 - 4qx + 4q^2 = 0​

Answer 1

Answer:

1) y^2 +2√3y +3=0

y^2 +(√3)^2 + 2.y.√3 =0

(y+√3)^2=0

(y+√3)(y+√3)=0

2) x^2 - 4qx +4q^2 =0

x^2 + (2q)^2 - 2.x.2q =0

(x-2q) ^2=0

(x-2q) (x-2q) =0

Hope u understand.

If no ask again.