Using factorisation, solve:
(x-2)(2x+3)=3(x-4)(x+8)
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Step-by-step explanation:
(x-2)(2x+3)=3(x-4)(x+8)
x(2x+3)-2(2x+3)=(3x-12)(x+8)
2x²+3x-4x-6=3x(x+8)-12(x+8)
2x²+3x-4x-6=3x²+24x-12x-96
Shifting LHS to RHS
3x²-2x²+24x-12x-3x+4x-96+6
x²+13x-90
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