Question

using Fermi function ,obtain the value of F(E) for E-Ef=0.01 ev at 200k​

Answer 1

Given:

E - Ef = 0.01 eV

Temperature T = 200 K

To find:

f( E ) =?

Step-to-step-explanation:

• According to the Fermi function, the probability of that particle will have energy E is given by:

      $\displaystyle f(E) = \frac{1}{e^\frac{{E-E_f}}{KT} +1}$

      where

      f( E ) = the probability of occupying energy level E

      $E_f$ = fermi energy

      T = temperature

      K = Boltzmann constant

• We know that the value of the Boltzmann constant is 8.6173 x 10⁻⁵ eV K⁻¹.

        i.e. K = 8.6173 x 10⁻⁵ eV K⁻¹

• Put the given values in the above formula of the fermi equation.

       $\displaystyle f(E) = \frac{1}{e^\frac{{0.01}}{8.6173 \times 10^{-5} \times 200} +1}$

       f( E ) = 0.0085 eV

• Hence, the required value is 0.0085.