Question

Using first principle differentiate tan vx, with respect to x.​

Answer 1

$\bf{ANSWER:}$

$\frac{d}{dx} \;tan(vx) = sec^2(vx) \;*\;v + x\frac{dv}{dx}$

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Answer 2

$\tt{Question :-}$

⟹ Using first principle differentiate tan vx, with respect to x.

$\tt{Answer :-}$

$\sf{= > \frac{d}{dx} \: \: tan(vx) = {sec}^{2} (vx) \times v + x \frac{dv}{dx}}$

Hope it helps you dear