Question

using formula expand 81p³-192q³
tell me fast answer any way​

Answer 1

Answer:

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Answer 2

Answer:

Factor

==>81p3−192q3

==>3 out of 81p3−192q3.

==>3out of 81p3.

==>3(27p3)−192q3

3 out of −192q3.

==>3(27p3)+3(−64q3)

3 out of 3(27p3)+3(−64q3).

3(27p3−64q3)

Rewrite

27p3as (3p)3.

3((3p)3−64q3)

Rewrite

64q3as (4q)3.

3((3p)3−(4q)3)

Since both terms are perfect cubes, factor using the difference of cubes formula,

a3−b3=(a−b)(a2+ab+b2)

where

a=3p and b=4q.

==>3((3p−(4q))((3p)2+3p(4q)+(4q)2))

Simplify.

==>3((3p−4q)(9p2+12pq+16q2))

Remove unnecessary parentheses.

==>3(3p−4q)(9p2+12pq+16q2)