Question

using formula for squaring binomial , evaluate the following.

${(101)}^{2}$

Answer 1

Hello...
Answer...

Solution :

We have

${(101)}^{2} = {(100 + 1)}^{2} \\ \\ = {(100)}^{2} + 2 \times 100 \times 1 + {(1)}^{2} \\ \\ = 10000 + 200 + 1 \\ \\ = 10201$


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Answer 2

$( 101)^{2}$
=$(100 + 1)^{2}$

Now,
$(a+b)^{2} = a^{2} +2ab+ b^{2}$

So,
$(100 + 1)^{2}$
= $100^{2} + 2*100*1 + 1^{2}$
= 10000+200+1
= 10201

(101)^2 = 10201.