Math, asked by siyonminj81, 7 months ago

using formula let's show that
(l+m)²=(l-m)²+4lm​

Answers

Answered by asifkhan070305
0

Answer:

(l + m)² = l² + m² + 2lm----------let this is equation 1

(l - m)² = l² + m² - 2lm

(l - m)² + 4lm = l² + m² - 2lm + 4lm

= l² + m² + 2lm

from equation 1 we know

l² + m² +2lm = (l + m)²

Answered by ranjeetdhillon143
0

Answer:

4lm = 4lm or 0

Step-by-step explanation:

WE APPLY ( a +b)^2 and (a-b)^2 FORMULA

l^2 + m^2 + 2lm = ( l^2 + m^2 +2lm) + 4lm

NOW WE TAKE WHOLE BRACKET FROM R.H.S TO L.H.S BY CHANGING SIGNS

l^2 + m^2 + 2lm - l^2 - m^2 + 2lm = 4lm

l^2 AND m^2 CANCEL WITH EACH OTHER BECAUSE OF OPPOSITE SIGNS

2lm + 2lm = 4lm

4lm = 4lm

OR

4lm - 4lm = 0

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