using formula let's show that
(l+m)²=(l-m)²+4lm
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Answered by
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Answer:
(l + m)² = l² + m² + 2lm----------let this is equation 1
(l - m)² = l² + m² - 2lm
(l - m)² + 4lm = l² + m² - 2lm + 4lm
= l² + m² + 2lm
from equation 1 we know
l² + m² +2lm = (l + m)²
Answered by
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Answer:
4lm = 4lm or 0
Step-by-step explanation:
WE APPLY ( a +b)^2 and (a-b)^2 FORMULA
l^2 + m^2 + 2lm = ( l^2 + m^2 +2lm) + 4lm
NOW WE TAKE WHOLE BRACKET FROM R.H.S TO L.H.S BY CHANGING SIGNS
l^2 + m^2 + 2lm - l^2 - m^2 + 2lm = 4lm
l^2 AND m^2 CANCEL WITH EACH OTHER BECAUSE OF OPPOSITE SIGNS
2lm + 2lm = 4lm
4lm = 4lm
OR
4lm - 4lm = 0
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