Question

Using fundamental theorem of arithmatic find hcf of 26,51,91
plss answr

Answer 1

Let's find out the L.C.M of any two numbers say

91 and 51

91 = 51 × 1 + 40

51 = 40 × 1 + 11

40 = 11 × 3 + 7

11 = 7 × 1 + 4

7 = 4 × 1 + 3

4 = 3 × 1 + 1

3 = 1 × 3 + 0

So the H.C.F is 1

Now lets find the H.C.F between 1 and 26

26 = 1 × 26 + 0

so the H.C.F = 1

so the H.C.F of 26,51,91 is 1.

Hope it helps.