Question

using gauss law elimination methid fund the value of x and y 5x+2y =3 -3x+3y =15​

Answer 1

Answer:

5x+2y=3----------1

-3x+3y=15----------2

eq1 multiply by 3 and 2 by 5

15x+6y=9------------3

-15x+15y=75----------4

eq3+4

15x+6y=9

+ -15x+15y=75

21y=84

y=84/21

y=4

Now

put y=4 in eq 1

5x+2y=3

5x+2×4=3

5x+8=3

5x=3-8

5x=-5

x=-5/5

x=-1