Question

using gauss's law deduce an expression for the electric field intensity at any point due to a thin infinitely long wire of linear charge density​

Answer 1

Answer:

epsilon =permittivity

R= distance from the wire

Let ∆ Be charge/unit length

Electric field = ∆/ 2π epsilonR

Answer 2

Answer:

epsilon =permittivity

R= distance from the wire

Let ∆ Be charge/unit length

Electric field = ∆/ 2π epsilonR