Question

Using Gauss theorem derive an expression for the electric intensity due to a charged thin spherical shell at (i) external point (ii) surface point (iii) internal point.​

Answer 1

Answer:

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Answer 2

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.

i) For a point outside the shell :

By Gauss's law, E.4πr

2

=

ϵ

0

Q

en

here r be the distance from centre of shell (r>R) and charge enclosed by surface Q

eq

=Q

So, E

out

=E=

4πϵ

0

r

2

Q

ii) For a point inside the shell :

By Gauss's law, E.4πr

2

=

ϵ

0

Q

en

here r be the distance from centre of shell (r<R) and charge inside the shell, Q

eq

=0

So, E

in

=E=0