Using graph find zeroes of i) y = x2
– 3x – 4, ii) yx2
– 6x + 9
Answers
Given : y = x² - 3x - 4 , y = x² – 6x + 9
To Find : Zeroes using Graph
Solution:
y = x² - 3x - 4
x y
-4 24
-3 14
-2 6
-1 0
0 -4
1 -6
2 -6
3 -4
4 0
5 6
-1 & 4 are zeroes of the x² - 3x - 4
x² - 3x - 4 = (x - 4)(x + 1)
y = x² – 6x + 9
x y
-2 25
-1 16
0 9
1 4
2 1
3 0
4 1
5 4
Only Zero is at 3
x² – 6x + 9 = ( x - 3)²
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