Question

Using graphical method drive the equation :v2=u2+2aS

Answer 1

BD=v

AO=CD=u

BC will be=v-u

Area under the velocity-time graph gives s(distance/displacement).

s=Area of trapezium AODB

=1/2(AO+BD)×AC

=1/2(u+v)×t

=1/2(u+v)(v-u/a) ( Since v=u+at, t=v-u/a )

2as=(v+u)(v-u)

2as= v^2-u^2

Therefore-

v^2=u^2+2as

Thank You.