using Henderson eqn calculate how much ch3coona is added to 1 lit of 0.01 molar acetic acid to make a pH of 4.1 ( of for CH3 cooh is 1.8 × 10-5)
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For (a), the Henderson-Hasselbalch equation, pH=pKa+log([A−]/[HA]), comes in handy. Because your molarities and volumes of the acid and its conjugate base are equal, this indeed reduces to simply pH=−log(6.3⋅10−5).
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using Henderson eqn calculate how much ch3coona is added to 1 lit of 0.01 molar acetic acid to make a pH of 4.1 ( of for CH3 cooh is 1.8 × 10-5)
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