Question

using
Heron's
formula, Find the
area
of
a
triangle
whose sides are.1.8,8,8.2​

Answer 1

$= \sqrt{9(9 - 8)(9 - 1.8)(9 - 8.2)} \\ = \sqrt{9 \times 1 \times 8.2 \times 1.8} \\ = 3 \sqrt{7.2 \times 1.8} \\ = 3 \sqrt{9 \times 0.8 + 9 \times 0.2} \\ = 9 \sqrt{0.1}$

= 43.46

hope it helps you.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Area\:of\:triangle=7.2\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle = 1.8,8,8.2} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Area \: of \: triangle = ?}$

• According to given question :

$\bold{As \: we \: know \: that \: herons \: formula} \\ : \implies s = \frac{a + b + c}{2} \\ \\ : \implies s = \frac{1.8 + 8+ 8.2}{2} \\ \\ : \implies s = \frac{18}{2} \\ \\ \green{ : \implies s = 9} \\ \\ \circ\: \bold{area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{9(9 - 1.8)(9- 8)(9 - 8.2)} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{9 \times 7.2 \times 1\times 0.8} \\ \\ : \implies \text{Area \: of \: triangle =} \sqrt{51.84} \\ \\ : \implies \text{Area \: of \: triangle =}7.2 \: cm^{2} \\ \\ \ \green{\therefore \text{Area \: of \: triangle = 7.2 {cm}}^{2} }$