Question

using heron's formula find the area of a triangle whose sides are 10cm 24cm 26cm​

Answer 1

Step-by-step explanation:

let a=10cm, b=24cm, c=26cm

s= 10+24+26

2

s = 60

2

s = 30

area of triangle = ✓s(s-a)(s-b)(s-c)

=✓30(30-10)(30-24)(30-26)

=✓30×20×6×4

=✓3×10×2×10×3×2×2×2

=3×10×2×2

=120cm^2

Answer 2

Answer:

$\: \: \: \: herons \: \: formula \\ \sqrt{s(s - a)(s - b)(s - c)} \\ a = 10cm \: \: \: \: b = 24cm \: \: \: \: c = 26cm \\ s = semiperimeter \: \\ s = \frac{a + b + c}{2} \\s = \frac{10 + 24 + 26}{2} \\ s = \frac{60}{2} \\ s = 30cm \\ area = \sqrt{s(s - a)s(s - b)s(s - c)} \\ = \sqrt{30(30 - 10)30(30 - 24)30(30 - 26)} \\ = \sqrt{30 \times 20 \times 30 \times 6 \times 30 \times 4} \\ = \sqrt{30 \times 30 \times 30 \times 2 \times 2 \times 20 \times 6} \\ = 30 \times 2 \sqrt{30 \times 20 \times 6} \\ = 60 \sqrt{3 \times 2 \times 5 \times 2 \times 2 \times 5 \times 3 \times 2} \\ = 60 \sqrt{3 \times 3 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5} \\ = 60 \times 3 \times 2 \times 2 \times 5 \\ = 60 \times 60 \\ = 3600c {m}^{2}$

I hope it will help you